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posted by  Blueidea on 10/11/2008 12:19:25 AM  |  status: Closed  

Show that at least one of U and W is a nonzero subspace of V and...

Course Textbook Chapter Problem
Linear Algebra N/A Linear Transformations N/A
Question Details:
Let T be a linear transformation on a vector space V such that T2=Id and TId.
Let U={vV: T(v)=v} and W={vV: T(v)=-v}. Show that
* at least one of U and W is a nonzero subspace of V
* UW={0}, V=U+W
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Sage
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posted by tdv (MNV) on 10/12/2008 11:10:23 AM  |  status: Live
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Response Details:
   We have T = Id. That T(T(v)) = v for all vin V.
   U={vV: T(v)=v} and W={vV: T(v)= - v}.
      
      We will show either U orW  is a nonzero subspace.
 
      Suppose U = 0 then T(v) v for all non zero vectors v in V.That is v-T(v) is nonzero vector
       Let w = v-T(v) ,
      Then T(w) = T(v) - T(T(v))= T(v)- v   =  -  (v - T(v) ) = -w.
      That is T(w) = - w which implies  w W and hence W is nonzero.
        So either U is nonzero or W is a nonzero subspace of V.
   
       Suppose v  UW. Then T(v) =v  and T(v) = -v. That is v = -v and hence v = 0.
       UW ={0}.
 
       Let v V. Let  w = v +T(v). Then T(w) = T(v) + T(T(v)) = T(v) + v = w
      That is w U. Then w/2 U
      Let w' =v - T(v). Then T(w')  = -w'. Hence w'  W. w'/2 W
  Now v = w + w' U+W.
So V is contained in U + W.Since U and W are subspaces of V, U+W is contained in V
Hence V =U+W.
 
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