Q BgQuestion:

Pupil
Karma Points: 77
Respect (94%):
posted by  nicandro@hawaii.ed on 10/6/2008 7:27:01 PM  |  status: Live  

funcion of the radius

Course Textbook Chapter Problem
Precalculus Precalculus: Mathematics for Calculus (5th) by Stewart, Redlin, Watson 2.6 1
Question Details:
The volume of a cylinder is 20 cu. in. Express the total surface area of the cylinder as a function of the radius r of the base.
Hope it helps

AAnswers:

Answer Question
Scholar
Karma Points: 285
(HB)
posted by chumchees on 10/6/2008 7:45:27 PM  |  status: Live
Asker's Rating: Somewhat Helpful   
nicandro@hawaii.ed's comment:
"thank you"
Response Details:
volume = πr2h
       20 = πr2h            solve for h
         h = 20 / πr2
 
Surface area = 2πr2 + 2πrh
              SA = 2πr2 + 2πr(20 / πr2)         sub in for h
                    = 2πr2 + (40πr / πr2)
Apprentice
Karma Points: 108
posted by Chris_3eb on 10/6/2008 8:25:50 PM  |  status: Live
Asker's Rating: Helpful   
nicandro@hawaii.ed's comment:
"thanks its alot clearer and it is the same answer that i got just different"
Response Details:
You need to represent the surface area as a function of the radius (r) of the base which means instead of having a number for S.A. you will have some number times r.
 
The volume of a cylinder is as follows:
 
v = (area of base) * (height)
v = (πr2) * (height)
20 = πr2h
 
now solve for height in terms of r (treat r as a number, not a variable)
h=20/πr2
 
Surface area is:
 
SA= 2(area of base) + (circumference of base * height)
 
SA = 2(πr2) + 2πrh
 
then plug h in from earlier
 
SA = 2(πr2) + 40πr/πr2
 
SA = 2(πr2) + 40/r
 
The main thing to keep in mind is that you just treat r like an ordinary number not a variable
Pupil
Karma Points: 77
posted by nicandro@hawaii.ed on 10/6/2008 8:52:44 PM  |  status: Live
Asker's Rating: N/A-Posted by Person Asking Question   
Response Details:
so
 
then
 
 
now
 
 
okay i believe in order to make it nice we should get a common denominator
 
 
here we can factor
 
 
 
alright
 
what do you think?
 
 
Hope it helps
Answer Question
Ask New Question

Join Cramster's Community

Cramster.com brings together students, educators and subject enthusiasts in an online study community. With around-the-clock expert help and a community of over 100,000 knowledgeable members, you can find the help you need, whenever you need it. Join for free today » How Cramster is different than tutoring »