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posted by  naladog on 10/8/2008 7:51:18 PM  |  status: Closed  

consecutive iintegers

Course Textbook Chapter Problem
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Question Details:
The larger of tow consecutive integers is more than half the smaller integer. Find the numbers
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posted by VietSpeed on 10/8/2008 8:01:47 PM  |  status: Live
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Response Details:
2 and 3.

x is the lower integer
x + 1 is the next integer

So

x + 1 = x + (x/2)
x + 1 = 3x / 2
2x + 2 = 3x
x = 2


Sage
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posted by rapunzel on 10/8/2008 8:16:38 PM  |  status: Live
Asker's Rating: Helpful   
Response Details:
x=1st number
x+1 = 2nd number
  multiply each side by 2 to get rid of the fraction
2(x+1)>x         apply distributive law
2x+2>x            subtract x from each side
x+2>0              subtract 2 from each side
x>-2

x+1>-1
Good Luck!
Pupil
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posted by EMFN on 10/8/2008 10:46:10 PM  |  status: Live
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Response Details:
The larger of two consecutive integers is more than half the smaller integer. Find the numbers.
 
Let x = smallest integer
 
Let x + 1 = the larger of the two
 
The larger of the two = (1/2) (x) + x...The extra x came from the fact that the question said "...is more" The word more is associated with addition in word problems.
 
 
We get this:
 
2x + 2 = 3x
 
2 = 3x - 2x
 
2 = x
 
The first number is 2.
 
The second number would be x + 1 or 2 + 1 = 3.
 
The numbers are 2 and 3.
 
=============================
 
How do we know that x = 2 is right?
 
We can plug x = 2 into the original equation and simplify.
 
If get the same answer on both sides of the equation, then we will know that x = 2 is correct.
 
THE PROVE:
 
....This is our original equation that was made from the information in the word problem.
 
 
 
= 3....It checks!
 
Since we got the same answer on both sides of the equation (3 = 3), this is our prove that
x = 2 is the correct answer, which led us to find the two consecutive numbers being 2 and 3.
 
Is this clear?
 
 
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