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posted by  studyingmama on 10/11/2008 2:09:01 PM  |  status: Live  

check my work/word problem

Course Textbook Chapter Problem
Algebra N/A N/A N/A
Question Details:
Would somone please check my work on this word problem? I think I got it, but I'm not sure.
 
As a calf grows it needs more milk for nourishment. The number of pounds of milk, M, required by a calf weighing x pounds can be estimated by the formula
 
Estimate the number of poundsof milk required by a calf with the weight of 300 pounds.  I got the following:
 
m= -5+          m= 256 pound of milk.
Is this correct or would it be 256 pounds of milk? Or am I way off base?
studyingmama
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Oracle
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posted by Ctrl on 10/11/2008 2:35:06 PM  |  status: Live
Asker's Rating: Lifesaver   
studyingmama's comment:
"Thank you. I see what I did wrong."
Response Details:
you are ok until :



Keep solving this you get:

(Note: the simplifies to , its no big deal if you solve with a calculator, either way you will get the right answer)

  <----I solved the 3 times the square root of 174 with a calculator

pounds of milk required



Scholar
Karma Points: 294
posted by Dio1080 on 10/11/2008 2:41:00 PM  |  status: Live
Asker's Rating: Helpful   
studyingmama's comment:
"Thank you for your help."
Response Details:
This is what I got:

m= -5+√(6.7(300)-444)

m=-5+√(2010-444)

m= -5+√(1566)

Pull all perfect square roots out from under the radical.  In this case remove the 3 because it is a perfect square.

m=-5+3√(174)

m = 34.5727

I hope this helps

I always rate lifesaver, but make sure you do the same to me.
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