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posted by  Crusoe on 5/23/2008 2:54:51 AM  |  status: Live  

Rolle's Theorem and the Mean Value Theorem

Course Textbook Chapter Problem
Calculus mat112p 1 2
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If
Check the hypothesis of Rolle's Theorem and the Mean Value Theorem and find a value of  c that makes the appropriate conclusion true for the following function;
 in the interval
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posted by radne on 5/23/2008 3:16:00 AM  |  status: Live
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f(a) = f(b) [part of rolle's]
f is continuous on [-2,2]           [part of rolle's and mean value theorem]
f is differentiable on (-2,2)        [part of rolle's and mean value theorem]

So the hypothesis of rolle's theorem is satisfied (as well as mean value theorem)

Which means we should be able to find some c on (-2,2) such that









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posted by Puksa on 5/23/2008 3:26:21 AM  |  status: Live
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Rolle's theorem essentially states that a smooth function, which attains equal values at two points, must have a stationary point somewhere between them.

f'(c)= 2x   -> f'(c)=0 -> stationary point is at x=0

MVT -> f(2)-f(-2) / 4  = f'(c)
f(2)=5 and f(-2)=5
->Rolle's theorem is a special case of the MVT -> f(a)=f(b)

The stationary point is at c=0









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posted by A-Rod 7821 on 5/23/2008 10:54:56 AM  |  status: Live
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Theorem 3.4 The Mean Value Theorem
If f is continuous on the closed interval [a,b] and differentiable on the open interval (a,b), then there exists a number c in (a,b) such that .
 
Theorem 3.3 Rolle's Theorem
Let f be continuous on the closed interval [a,b] and differentiable on the open interval (a,b). If f(a)=f(b) then there is at least one number c in (a,b) such that f '(c)=0.
 
First Rolle's Theorem Check
 in the interval
c = 0
F is also continuous and differentiable on the closed interval [-2,2]. Therefore you can apply Rolle's Theorem.
 
Lets Check Mean Value Theorem
f is continuous and differentiable on the closed interval [-2, 2].
Because f satisfies the condtions of the Mean Value Theorem, there exists a least one number c in (-2, 2) such that f '(c)=0. Solving the equation f '(x)=0 yields f '(x)=2x=0 which implies that x=0. So in the interval (-2, 2) you can conclude that c=0.
 
 
 
 
 
 
 
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