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posted by  Brasilguy04 on 11/26/2008 7:57:57 PM  |  status: Closed  

area of region

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Calculus N/A N/A N/A
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Find the area of the region inside: r = 5 \sin \theta but outside: r = 2
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posted by Jasminek on 11/27/2008 12:12:35 AM  |  status: Live
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"thanks"
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posted by Bpanda on 11/27/2008 10:27:01 AM  |  status: Live
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Brasilguy04's comment:
"thanks"
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Let's see when  5.sinθ =  2    ===>  sinθ = 2/5    ===>  θ = 0.412    or  θ = 2.73
 
therefore:
 
 
 
 
 
 
hope this helps
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