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posted by  rose13 on 11/26/2008 10:55:01 PM  |  status: Live  

Integration

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How do I integrate  
Tags: Calculus

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posted by roydesoto on 11/26/2008 11:20:49 PM  |  status: Live
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let u = x4 so du = 4x3 dx

integral becomes
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posted by The Joker on 11/27/2008 12:09:11 AM  |  status: Live
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Ok so I do agree with letting u=ex4 so du=4x3
but 24(3x2)+ 4x3
/72x2 + 4x3 dx
=
 So that changes the integral if you set only x4= u. But of course I could be wrong, im just letting in a suggestion.
I do hope this helps!
 
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posted by vladittude0583 on 11/27/2008 1:41:18 AM  |  status: Live
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posted by A-Rod 7821 on 11/27/2008 6:45:20 PM  |  status: Live
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Use U-Substitution here:
let u=x4
du=4x3dx
du/(4x3)=dx
The integration formula for eu is:
Substitute back in what you set u as.
----(ANSWER)----
 
 
 
 
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posted by borden on 11/27/2008 10:47:49 PM  |  status: Live
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the very first techinque in solving integral problems is to see if the deverivate of one of the functions is in the integral if it isthen the power rule = f(x)^n+1/n+1
 
the deverivate is in there because the deverivate of x^4=4x^3
The 24 is a constant and can be factored out of the integral by the constant multiple rule and so can the 4 which=6
 
the integral of e^x^4=E^x^4+c
 
Final answer is 6e^x^4 + C
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