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posted by  ellen green on 11/30/2008 12:13:19 PM  |  status: Live  

WILL RATE LIFESAVER>>>INTEGRALS!

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integral with 9 on top, 0 on the bottom, then..square root of 2u+absolute value of (u-6)(u-3), *du
Tags: Calculus
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posted by Altair on 11/30/2008 12:22:30 PM  |  status: Live
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posted by Naeem on 11/30/2008 12:39:48 PM  |  status: Live
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I think you mean




 
now do the 2nd integerl, first graph and see how it looks


                                            =  45/2  - (-9/2) + 45/2  = 49.5

so total integerls =    49.5 + 18√2
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posted by Bpanda on 11/30/2008 12:50:40 PM  |  status: Live
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first let's find the sign of  the product ( u - 6)( u - 3)
 
the two roots are 3 and 6
 
when  0 < x < 3    and  6 < x < 9     ===>  ( u - 6)( u - 3) > 0   ===>  |  ( u - 6)( u - 3) | =  ( u - 6)( u - 3)
 
when  3 < x < 6             =========== >  ( u - 6)( u - 3) < 0   ====> |  ( u - 6)( u - 3)| = -  ( u - 6)( u - 3)
 
the second integral should be splitted in three parts:
 
 
 
 
hope this helps
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