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posted by  Math I-6 on 7/27/2007 9:27:37 AM  |  status: Live  

Drug usage6

Course Textbook Chapter Problem
Calculus N/A N/A N/A
Question Details:
Jane took 100 mg of a drug in the morning and another 100 mg of the same drug at the same time the following morning. The amount of drug in her body t days after the first dosage was taken is given by
 
          { 100e-1.4t                   0 < t < 1
A(t) = 
          {100(1 + e1.4)e-1.4t      t > 1

What was the amount of drug in Jane's body immediately after taking the second dose?
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Oracle
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(Ecole Polytechnique Fédérale de Lausanne)
posted by Golden Monkey on 7/27/2007 2:05:05 PM  |  status: Live
Asker's Rating: Helpful   
Response Details:
This is a weird question... and by that I mean it's not clear on what it wants you to do. But based on the info given, she takes the second dosage at t = 1. And you are given a function for A for t = 1 (the second function). So the best I can tell, they just want you to plug in t = 1 to the second function:
 
   A(1) = 100 (1 + e1.4 ) e-1.4*1 =  124.7 mg
Tags: Math, Calculus
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posted by Rhelliane on 7/27/2007 2:05:26 PM  |  status: Live
Asker's Rating: Lifesaver   
Math I-6's comment:
"Thanks"
Response Details:
 This is a pharmacy question. I am not a pharmacist but a herbalist.
   Looking at the given equation and question. Use the  second equation since it is asking for immediate reaction of the drug at t more than or equal to 1 or 1 day minimum. Substititute in the equation at t=1
  A(t)=100(1+e 1.4)e^-1.4t=  100(4.80559456)(0.24659693)= 118 .504mgs. or 119 mgs app.

  Hope this helps.
 Oracle beat me by a second . My  idol. But he didnt multiply the the e. Check it well.
 "Great works are performed not by strength, but by perseverance." 
Tags: Math, Calculus
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