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posted by  tierra-y-libertad on 10/1/2007 1:38:34 PM  |  status: Live  

Materials Science and Engineering 7th ed simple Question

Course Textbook Chapter Problem
Chemical Engineering Materials Science and Engineering 7th ed, Callister 4 7
Question Details:
I need to know how to solve this simple question:
What is the composition, in atom percent, of an alloy that consists of 92.5 wt% Ag and 7.5 wt% Cu?
and if is possible the opposite way, from at% to wt%. Thanks!

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posted by obscur on 10/1/2007 2:50:11 PM  |  status: Live
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tierra-y-libertad's comment:
"thanks"
Response Details:
use eq.     CAg = [(CAgACu) / [(CAgACu) + (CCuAAg)] ] x 100
 
CAg = 92.5   (wt % of Ag) given
ACu = 63.55 g/mol    (atomic weight of Cu)  tables
CCu = 7.5   (wt % of Cu) given
AAg = 107.87 g/mol  (atomic weight of Ag)  tables
 
CAg =[ [(92.5)(63.55)] / [(92.5)(63.55) + (7.5)(107.87)] ]x 100 = 87.9%
 
CCu = [(CCuAAg ) / [(CAgACu) + (CCuAAg)]] x 100
 
CCu =[ [(7.5)(107.87)] / [(92.5)(63.55) + (7.5)(107.87)]] x100 = 12.1%
 
The easiest way is to find one of the solutions and subtract that from 100. Because there can only be 100 %.
 
If we find CAg = 87.9%, then CCu would be 1 - 87.9 = 12.1%
 
From at% to wt% 
 
CAg = [CAgAAg / (CAgAAg + CCuACu)] x 100
 
       = [(87.9)(107.87) / [(87.9)(107.87) + (12.1)(63.55)]] x 100 = 92.5
 
CCu = [CCuACu / (CCuACu + CAgAAg)] x 100
 
      = [(12.1)(63.55) / [(12.1)(63.55) + (87.9)(107.87)]] x 100 = 7.5
 
 
 
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