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posted by  The VC on 10/25/2007 9:18:04 PM  |  status: Live  

Completing Addition Reactions

Course Textbook Chapter Problem
Organic Chemistry WORKSHEET N/A N/A
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Hi,

I was wondering if somebody could help me out with this reaction.  These are supposed to be 3 separate reactions each with a slightly different reactant each time.  I would appreciate any help I can get on this problem!  <Also, could you please explain how you got the final product and whether there is indeed more than one product>



Many Thanks,

Andrew
The VC
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posted by Jfcap on 10/25/2007 11:09:37 PM  |  status: Live
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The first one is a markovnikov addition.  A Markovnikov addition is where the bromine will attach to the more substituted carbon.  In this case it is the carbon with the methyl group attached to it.

On my drawing...the reactant should have a -CH3 group on carbon 1 (like in the original problem)
 
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posted by Jfcap on 10/25/2007 11:13:27 PM  |  status: Live
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The second one is very similar, except it form an anti-markovnikov bond, where the bromine will go to the least substituated carbon.


On my drawing...the reactant should have a -CH3 group on carbon 1 (like in the original problem)
 
Guru
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posted by kdog on 10/25/2007 11:13:54 PM  |  status: Live
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Response Details:
Markovnikov's rule. In the addition of HX to an alkene, the H attaches to the carbon with the fewest alkyl substituents and the X attaches to the carbon with the most alkyl substituents.
 
Water and H + make an alcohol
 
 
Peroxides cause the Br to add anti-markovnikov
 
Hope this help.. PLEASE RATE
 
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