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posted by  shake-n-bake on 11/23/2007 8:59:23 AM  |  status: Live  

Take Home Test

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A feverish chemistry student weighing 75 kg was immersed in 400 kg of water at 4.0oC in an attempt to reduce the fever.  The student's body temperature eventually dropped from 40oC to 37oC.  Assuming the specific heat of the student to be 3.77 J/goC, what was the final temperature of the water?  Assume that the water retained all of the heat withdrawn from the student.

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posted by bookworm2 on 11/23/2007 12:43:49 PM  |  status: Live
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shake-n-bake's comment:
"Thanks, that help a lot."
Response Details:
ms = 75kg
cs = 3.77J/gC = 3.77KJ/KgC
Δt = 3C
 
mw = 400kg
cw = 4.19J/gC = 4.19KJ/gC
Δt =?
 
Energy lost = energy gained
 
mscsΔts =  mwcwΔtw
mscsΔt / mwcw = Δtw
 
(75kg)(3.77KJ/KgC)(3C) / [(400Kg)(4.19KJ/KgC)] = 0.51C
 
Final Temp of water = 4 + 0.51 = 4.51C
 
 
 
 
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