Q BgQuestion:

Rookie
Karma Points: 2
Respect (100%):
posted by  yamykytiv on 2/21/2008 6:51:14 PM  |  status: Live  

CHEM HELP

Course Textbook Chapter Problem
N/A N/A N/A N/A
Question Details:
the half-life of a firt order decomposition reaction is 2.36 hours. If the initial concentration of reactant is 0.52M, what is the concentration of reactant after 752 seconds?

AAnswers:

Answer Question
Pupil
Karma Points: 63
posted by Clark on 2/21/2008 8:11:21 PM  |  status: Live
Asker's Rating: Helpful   
yamykytiv's comment:
"THANK YOU!!!!!!"
Response Details:
In order to solve this question you have to use the half - life formula:
AL = AO(1/2)t/n
 
AL is your remaining concentration, AO is your original concentration, t represents the time and n is the half life.
Now in this case, 0.52M will be your AO, the 'n' will be 2.36 hours and the time will be 752 seconds (dont forget to convert seconds into hours!!) 
Now all you have to do is plug these numbers into your equation and solve for AL, which will be your concentration after 752 seconds.  I hope this helps!!
Answer Question
Ask New Question

Join Cramster's Community

Cramster.com brings together students, educators and subject enthusiasts in an online study community. With around-the-clock expert help and a community of over 100,000 knowledgeable members, you can find the help you need, whenever you need it. Join for free today » How Cramster is different from tutoring »