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posted by  Chem Eyez on 3/22/2008 10:01:13 AM  |  status: Live  

Help if u can!!! %Ionization

Course Textbook Chapter Problem
General Chemistry Chemistry: The Central Science (10th) by Brown, Lemay, Bursten N/A N/A
Question Details:
(a) Calculate the percent ionization of 0.095 M lactic acid (Ka = 1.4 10-4).
%

(b) Calculate the percent ionization of 0.095 M lactic acid in a solution containing 0.048 M sodium lactate.
%

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posted by larios on 3/22/2008 4:11:36 PM  |  status: Live
Asker's Rating: Helpful   
Chem Eyez's comment:
"Thank u very much it was very helpful eventhough the first part was incorrect"
Response Details:
HC3H5O3   +  H2O---- H3O + C3H5O3
I  0.095M         ---           0             0
C  -X                               X             X
E 0.095-X                      X           X
 
1.4x10^-4=     X^2     let x be small and solve for X
                 0.095-x
X= 0.00365  x 100%= 58.7 %
        0.095
 
HC3H5O3   +  H2O---- H3O + C3H5O3
I  0.095M         ---           0          0.048
C  -X                               X             X
E 0.095-X                      X           0.048+X
 
1.4x10^-4= X(0.048+X)
                     0.095-X
X= 2.77e-4 x 100%= 0.292%
        0.095
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