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posted by  PoleDancersRock on 5/8/2008 12:19:08 AM  |  status: Live  

molarity

Course Textbook Chapter Problem
General Chemistry tro 11 and 12 N/A
Question Details:
A solution was prepared by dissolving 38.0 g of \rm KCl in 225 \rm g of water.
Calculate the mass percent of \rm KCl in the solution


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Sage
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posted by Jesley on 5/8/2008 12:41:34 AM  |  status: Live
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Response Details:
 
mass of KCl ,m1= 38.00 g
mass of water, m2= 225 g

total mass, m= m1+m2= 38+225=263 g
mass fraction of KCl in the solution= (m1/m)*100=(38/263)*100=14.45%
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posted by maldo602 on 5/8/2008 12:50:36 AM  |  status: Live
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"I LOVE HOW YOU EXPLAINED THIS....IT ONLY LET ME RATE YOU 7 AS THE HIGHEST.....BUT YOU DESERVE MORE BECAUSE YOU EXPLAINED IT IN A DIFFERENT WAY! THANKS"
Response Details:
Mass percent is the mass of a substance in a mixture as a percentage of the mass of the entire mixture. So,  you'll have   X 100 =  X 100 =  14.4% 
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