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posted by  neha2008 on 7/15/2008 10:25:14 PM  |  status: Live  

temperature???hmm??help pleaz

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a thermometer gives a reading of 96.1 degree fahrenheit +/ - 0.2 degree fahrenheit. what is the temperature in celsius? what is the uncertainity?
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posted by Jack Alope on 7/15/2008 11:52:06 PM  |  status: Live
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neha2008's comment:
"thanx"
Response Details:
[°F] = [°C] × 95 + 32
[°C] = ([°F] − 32) × 59
 
Temperature + uncertainty in Celsius =
35.6 +- 0.11
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posted by Jesley on 7/15/2008 11:54:07 PM  |  status: Live
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neha2008's comment:
"thanx"
Response Details:
T (0F)=1.8*T(0C)+32
96.10F=1.8T(0C)+32
T(0C)=(96.1-32)/1.8 = 35.610C
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posted by neha2008 on 7/17/2008 2:01:48 PM  |  status: Live
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Response Details:
thanx. but i didnt get de uncertainity part. how did u get +/- 0.11. can u pleaz explain? 
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posted by Jack Alope on 7/21/2008 9:28:25 PM  |  status: Live
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neha2008's comment:
"thank u so much"
Response Details:
 
[°F] = [°C] × 95 + 32
[°C] = ([°F] − 32) × 59
 
Temperature + uncertainty in Celsius =
35.6 +- 0.11

I calculated the uncertainty as 0.11 for Celsius, because the Farenheit uncertainty of 0.2 degrees means that the temperature falls between 96.3° and 95.9°. These points of extrema in Celsius are 35.72° and 35.5°. The difference between these two numbers is 0.22, thus the midpoint is (35.7 +(0.22/2)) or (35.5 - (0.22/2)), which both produce the midpoint of 35.6° and uncertainty of (0.22/2) = +-0.11
I hope this helps!
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posted by Cowboy15 on 7/21/2008 9:52:22 PM  |  status: Live
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neha2008's comment:
"thanx"
Response Details:
  T (0F)=1.8*T(0C)+32
 
96.10F=1.8T(0C)+32
 
T(0C)=(96.1-32)/1.8 =
 
ANSWER = 35.610C
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