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posted by  NEED------HELP on 8/26/2008 4:23:03 PM  |  status: Live  

Gen. Chem, please help

Course Textbook Chapter Problem
General Chemistry the central science 6th edition 10 N/A
Question Details:
A closed end manometer was attached to a vessel containing argon. If the difference in the mercury levels in the two arms of the manometer was 12.2cm and the atmospheric pressure was 783 torr, what was the pressure of the argon in the container?
 
A) 122 torr,  B) 661 torr,  C) 771 torr,  D) 795 torr  ????? please help thanks

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posted by kwyjibo on 8/26/2008 6:28:51 PM  |  status: Live
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NEED------HELP's comment:
"thanks"
Response Details:
pressure diff = 12.2cm*(760 torr/760 mmHg)*(1000 mm/100 cm) = 122 torr

Pressure argon = 783- 122 = 661 torr; B)
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