home > q&a board > chemistry > topic: calculating mol and grams of iron! please help!

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posted by  tored ryan on 8/27/2008 6:01:59 PM  |  status: Live  

calculating mol and grams of iron! Please help!

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Question Details:
Consider the reaction of 38.0 g of iron as follows:
4Fe + 3O2 2Fe2O3
How many moles of iron react? mol
How many moles of oxygen must react? mol
How many moles of product form? mol
What mass of product forms? g
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Sage
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posted by kwyjibo on 8/27/2008 7:03:18 PM  |  status: Live
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tored ryan's comment:
"Thanks a lot!"
Response Details:
38 g iron *(1mol/55.845 g) = 0.68 mol

b) 0.68 mol Fe*(3 mol O2/4molFe) = 0.51 mol O2

c) 0.68 mol Fe*(2mol Fe2O3/4mol Fe) = 0.34 mol Fe2O3

d) 0.34 mol*(159.69 g/mol ) = 54.29 g
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posted by Kaiouji on 8/27/2008 7:06:02 PM  |  status: Live
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tored ryan's comment:
"Thanks!"
Response Details:
so to calculate we use stoichiometry

if we use 38grams of Fe, then that means
that means =1.02 mol O
0.34 mol Fe2O3 forms
54.29grams of product forms
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