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posted by  bnmcclen on 8/28/2008 8:54:13 AM  |  status: Live  

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Question Details:
What is the atomic mass of element X if 23.78 g XCl3 contains 4.81 g X?

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posted by Ricky Wilkins on 8/28/2008 11:58:06 AM  |  status: Live
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Response Details:
 1 mol of XCl3 contains  3 mols of Cl.
 But we have 23.78g of XCl3 contains 4.81g of X ,Thus the remaining weight corresponds to the mass of the Cl present in the given compound,Hence the mass of the Cl
                                                                    = 23.78 - 4.81
                                                                    = 18.97g
 we know that 1mol of Cl = 35g
  therefore 18.97g of Cl    = 0.542mol
1mol of XCl3  contains  3mol of Cl
 ∴0.542 mol of Cl present in mole of XCl3 = 0.542/3
                                                                  = 0.18 mol
0.18mol of X  =          4.81g
∴ 1 mol of X  =          26.72g
 This is the atomic weight of the X which indicates that the atom may be "Al" in th periodic table.
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posted by Xylene on 8/28/2008 12:45:27 PM  |  status: Live
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Response Details:
Before going for the sum we can have a wild guess the the chloride of Aluminium is AlCl3
there the atomic mass is  approximately 27
 
 
   23.78g of XCl3 contains 4.81g of X ,
                             = 23.78 - 4.81
                             = 18.97g
  1mol of Cl = 35g
  18.97g of Cl    = 0.542mol
1mol of XCl3  contains  3mol of Cl
0.542 mol of Cl present in mole of XCl3 = 0.542/3
                                                                  = 0.18 mol
0.18mol of X  = 4.81g
 1 mol of X  = 26.72g
 Atomic weight is app. = 27
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