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posted by  john l. on 9/9/2008 7:43:12 PM  |  status: Live  

Urgent Help Needed (LIFESAVER)

Course Textbook Chapter Problem
Physical Chemistry N/A N/A N/A
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posted by Jesley on 9/9/2008 9:12:30 PM  |  status: Live
Asker's Rating: Lifesaver   
john l.'s comment:
"Thank you so much for your help"
Response Details:
the reaction for the combustion of sucrose is
 
                 C12H22O11(s) + 12O2(g) ----->  12 CO2(g)  +  11 H2O(l)
the standard enthalpy change for the reaction is
 
 ΔH0rxn =ΣviHi[products] -ΣviHi[reactants]
             =[12  ΔH0f(CO2(g)) +11ΔH0f( H2O(l))] -[1ΔH0f(C12H22O11(s))+12ΔH0f(O2(g))]
            =[12(-393.5)+11(-285.8)]-[ΔH0f(C12H22O11(s))+12(0)]
  -5639.7KJ/mol  = -7865.8KJ/mol -ΔH0f(C12H22O11(s))
ΔH0f(C12H22O11(s)) = -2226.1KJ/mol
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