home > q&a board > chemistry > topic: question about 12.64 in cheng chemistry 9th edition

Q BgQuestion:

Scholar
Karma Points: 200
Respect (50%):
posted by  mykidshave4paws on 9/9/2008 10:40:41 PM  |  status: Live  

Question about 12.64 in Cheng chemistry 9th edition

Course Textbook Chapter Problem
General Chemistry Chemistry (9th) by Chang 12 64P
Question Details:
where did the 0.058 come from or how is that known?
Bonus Point Alert! Earn +4 additional karma points for helping this annual member.

AAnswers:

Answer Question
Sage
Karma Points: 4,684
posted by Jesley on 9/9/2008 10:57:33 PM  |  status: Live
Asker's Rating: Lifesaver   
mykidshave4paws's comment:
"thank you ever so much."
Response Details:
because there is 0.234mole of solute in 1kg of solvent, the number of moles of solute in
(25/1000)kg =0.025kg of solvent is
moles of solute = 0.025kg*(0.234mol/1kg) =5.85x10-3mol
the molar mass of solute is
molar mass = grams of solute/moles of solute
               =2.50g /5.85x10-3mol
                      =427.35g/mol
molar mass/empirical molar mass = (427.35g/mol)/(108g/mol)=3.9˜4
therefore the molecular formula is
(C6H5P)4 or C24H20P4
Answer Question
Ask New Question

Join Cramster's Community

Cramster.com brings together students, educators and subject enthusiasts in an online study community. With around-the-clock expert help and a community of over 100,000 knowledgeable members, you can find the help you need, whenever you need it. Join for free today » How Cramster is different from tutoring »

Need Help In

Useful Links