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posted by  sandybell on 9/11/2008 12:20:33 PM  |  status: Closed  

pH

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what is the pH of 0.5M acetic acid
 
please show how to do this
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posted by Bob on 9/11/2008 1:00:41 PM  |  status: Live
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sandybell's comment:
"thank you"
Response Details:
Here is a web-site that calulates the Ph for a .10m solution. You should be able to calculate your .5 m using the same procedure.
 
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posted by Xylene on 9/11/2008 1:29:41 PM  |  status: Live
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sandybell's comment:
"thank you"
Response Details:
  [H+] = √(Ka x C)
  where [H+]  is the concentration of the acid
   Ka is the dissociation constant of the weak acid which is constant
   C is the concentration of the weak acid (given)
From the above information you can calculate the value of [H+]
   therefore pH = -log [H+]
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