by using the formula of freezing point depression
ΔTf =Tf0 -Tf =Kf m
where, Tf0 =freezing point of pure solvent =0 oC
Tf =freezing point of solution =-2.34oC
Kf = freezing point depression constant =1.86oC/m
m= concentration of solute in molality =?
first determine 'm' using the formula
molality =moles of solute/mass of solvent in kg
moles of solute = m*(0.250kg)
molar mass ,Mm = mass/moles