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posted by  DASHIRA on 9/20/2008 1:02:12 PM  |  status: Closed  

MY FIRST QUESTION

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 Thanks for the warm welcome.

                     This is my first question here, so give me a break !

         10 ml of HCL with a purity of 33%(w/w) and a specific gravity of 1.1 are diluted with distilled water tomake 1 Liter of solution. Calculate it's Molarity and it's Normality.

                               What does Specific Gravity have to do with this ?

 

                          What is Purity, and what does (w/w) stand for?

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posted by Xylene on 9/20/2008 1:12:06 PM  |  status: Live
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DASHIRA's comment:
"GOOD FOR STARTERS. "
Response Details:
  Molarity = (% X sp.gravityX 10)/ gram molar mass
               = (33 X 1.1 X 10)36.5
               =9.945
for dilution  formula is V1M1 = V2M2
                                 10 X 9.945 = 1000 X M2
                                               M2  = 0.09945
Molarity and Normality is equal because the basicity of acid is one
  Therefore Molarity = Normality = 0.09945
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