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posted by  Soccer Mom on 10/2/2008 1:50:19 AM  |  status: Live  

chemical reactions

Course Textbook Chapter Problem
General Chemistry N/A 4 87
Question Details:
Some chemical reactions are best done in solution. If you had 101.3 mL of 0.215 M NaOH, how many milliliters of 0.545 M HCl would you need to have the same number of moles as found in the NaOH solution

__________mL
Soccer Mom
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(New Mexico Tech)
posted by The Joker on 10/2/2008 2:32:20 AM  |  status: Live
Asker's Rating: Helpful   
Soccer Mom's comment:
"Thank you for all your efforts and your time. "
Response Details:
Ok so here the problem is pretty straight forward...they want you to find the amount of ml of HCl...ok..whats our plan..
We need to set up a dimensional analysis so that we get the moles of HCL in ml...
so 0.545 M HCL* 1 mol HCL/35.453 g HCL*1 L/101.3 ml* 1 L /1000 ml* 40 g/1 mol NAOH=.00607=
6.07x10-3. Is your answer...
I hope this helps!
"I think I can safely say that nobody understands Quantum Mechanics"
-Richard Feyman.
".....(Fe)male...male with iron
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(Cramster SME)
posted by Neils on 10/2/2008 2:32:40 AM  |  status: Live
Asker's Rating: Lifesaver   
Response Details:
Formula:
              M1V1/n1 =M2V2/n2
 Where M1 = Molarity of NaOH = 0.215M            M2 =Molarity of HCl = 0.545M
             V1 =Volume of  NaOH  =101.3mL            V2  =Volume of  HCl = ?
             n1  =No.of mols of NaOH =1                      n2 =No.of mols of HCl = 1
         Here mentioned that the no.of mols of the two reactasnts are equal.So we neglected no.of mols in the formula.So the formula
       M1V1 ==M2V2
        V2 = M1V1 /M2
             =0.215M x 0.1013L/0.545M
             =0.0399L
             = 39.96mL     
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