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Scholar
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posted by  k8 on 10/9/2008 11:26:24 AM  |  status: Live  

Molarity problem

Course Textbook Chapter Problem
N/A Tro's book 4 444
Question Details:
A scientist wants to make a solution for tribasic sodium phosphate Na3PO4, for a lab experiment. How many grams of Na3PO4 will be needed to produce 375mL of a solution that has a concentration of Na+ions of 0.800 M?   How many moles of Na+ are in the solution?
 
Mass of Na3PO4 in grams g
 
I am lost with this problem. I really need help. Will rate. Thanks K8
Tags: Chemistry
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Sage
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posted by PubStomp on 10/9/2008 11:31:02 AM  |  status: Live
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k8's comment:
"Thank you"
Response Details:
so there will be 3 Na+ ions per mole of Na3PO4

You need .8 * .375 = .3 moles of Na3PO4 to have .8 Molarity if there were only 1 Na+

but since there are 3 you divide by 3 to have .1 Moles of Na3PO4


Molar mass of Na3PO4 = 163.940671 g/mol

so .1 *
Molar mass of Na3PO4 = 163.940671 g/mol

= 16.4 grams of Na3PO4


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