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posted by  qman on 10/9/2008 4:20:20 PM  |  status: Live  

help

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Question Details:

Calculate the pH of a 2.00 L solution containing 0.885 moles of hypochlorous acid (HClO) and 0.905 moles of NaClO. Given Ka  for HClO is 3.0 x 10-8.

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posted by ajw7989 on 10/9/2008 4:35:21 PM  |  status: Live
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qman's comment:
"thanks"
Response Details:
Ka = [H+] [base] / [acid}
 
3.0*10-8 = [H+]  .905/.885
 
[H+] = 2.934 x 10-8
 
ph = -log [H+]
 
pH = 7.53
 
which makes sense since there is  more base
 
 
 
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