CrCl3 will dissociate into Chromium and Chloride ions. Chromium ion requires 3 electrons to change into Chromium. i.e 3 moles of electrons are required to produce one mole of Chromium .
CrCl3 ↔ Cr+3 + 3 Cl-
Cr+3 + 3e- → Cr(S)
3 mol 1 mol
1 mole of Chromium = 51.99 g [ Molar mass of Cr = 51.99]
51.99 g of Chromium is producedafter taking 3 mol of electrons
17.33 g of Chromium is producedafter taking 1 mol of electrons
we know that 1 mol of electron represents 1 F = 96500 coulombs
35 g of Chromium is producedafter taking 2.01 mol of electrons (35 g*1 mol/17.33 g)
∴ 2.01*96500 coulombs would be required to electroplate 35.0 grams of chromium by passing an electrical current through a solution containing CrCl
3
194893.248 coulombs would be required to electroplate 35.0 grams of chromium by passing an electrical current through a solution containing CrCl3