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posted by  ProEliteMark on 9/11/2008 12:38:50 PM  |  status: Live  

number theory2134r

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Suppose that F1 ο G2 =F1 ο G1  then  F : S→ T, G1 : T → U, G2 : T →U,. Define a function  F : R2 ? R2 by F(x, y) = (x + y, x - y).  . Show that if F is onto, Suppose that G1 ο F = G2 ο F. Show by counterexample that if F is not onto then  show that if H is one-to-one, then G1 = G2. But this means one of two things,  H is not one to one, and if and only if

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posted by James(SME-Math) on 9/12/2008 12:41:44 AM  |  status: Live
Asker's Rating: Lifesaver   
ProEliteMark's comment:
"thank for all of them,. lol"
Response Details:
a)
H o G1 = H o G2
 
Suppose that H is one - to -one
 
To show that  G1 = G2
 
Let  tT.
 
Now H o G1(t) = H o G2(t)
 
=> H (G1(t))  = H( G2(t))
 
=> G1(t) = G2(t)       (since H is one - to -one)
 
=> G1 = G2
Hope this helps you..... 
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posted by iceberge on 10/20/2008 10:16:55 AM  |  status: Live
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Response Details:
F1 ο G1  then  F : S→ T, G1 : T → U, G2 : T →U,. Define a function  F : R2 ? R2 by F(x, y) = (x + y, x - y).  . Show that if F is onto, Suppose that G1 ο F = G2 ο F. Show by counterexample that if F is not onto then  show that if H is one-to-one, then G1 = G2. But this means one of two things,  H is not one to one, and i
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posted by Allie Boy on 10/20/2008 10:22:39 AM  |  status: Live
Asker's Rating: Helpful   
Response Details:
F1 ο G1  then  F : S→ T, G1 : T → U, G2 : T →U,. Define a function  F : R2 ? R2 by F(x, y) = (x + y, x - y).  . Show that if F is onto, Suppose that G1 ο F = G2 ο F. Show by counterexample that if F is not onto then  show that if H is one-to-one, then G1 = G2. But this means one of two things,  H is not one to one, and i
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