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Response Details:
Good day obscur!
Regarding with ypur query about the change of the unstretched length of the spring from 1m to 0.46m, the same force will be applied on the spring and that is still be equal to 298.434kg, hence, only the spring constant k will be change. Since the unstretched length becomes smaller, then the constant spring k will yield a larger value.
Again, to calculate the constant spring k:
According to Hooke's Law, the Force that elongates the spring is
directly proportional to its deformation, we insert a constant k to
eliminate the proportionality sign
F = kx
298.434 kg = k (0.46 m)
Therefore: k = 648.77 kg/m
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