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posted by  jerge on 9/23/2008 8:25:54 PM  |  status: Live  

differantial equations

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a certain business increase in value at a rate proportional to the square root of its current value. if this business was worth one million dollars two years ago and is worth 1.44 million dollars today, determine when it will be worth two million dollars.
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posted by velixy on 10/3/2008 10:50:04 AM  |  status: Live
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a certain business increase in value at a rate proportional to the square root of its current value. if this business was worth one million dollars two years ago and is worth 1.44 million dollars today, determine when it will be worth two million dollars.
 
N(t) = No .exp(rt)
 
t=0 ==> N(0) = No= 1 million dollars
 
t=2=>    N(2) = 1. exp(2.r) = 1.44 million dollars   today
 
                   exp(2.r) = 1.44  ==>  2.r = ln(1.44) ==> r = ln(1.44) /2 =0.182322
 
N(t) = No .exp(rt) ==> N(t) = 1 .exp(0.182322 t)
 
when
    1 .exp(0.182322 t) =  2  million dollars ?
 
  exp(0.182322 t) =  2  ==>  0.182322 t = ln(2) =>  t = ln(2)/ 0.182322= 3.80177
 
        4 years
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