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posted by  Sea Salt on 11/7/2007 10:13:54 PM  |  status: Closed  

Finding Kinetic Energy and Height

Course Textbook Chapter Problem
Calculus Based Physics N/A N/A N/A
Question Details:
 
a.) What is the kinetic energy of a 1200kg car moving at 25 m/s? In steps please.
Use KE = 1/2mv2
 
b.) How high up a frictionless hill could the above car coast? Use h=
 
 

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posted by ktqu on 11/7/2007 10:17:05 PM  |  status: Live
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Sea Salt's comment:
"Thank you so much for your help"
Response Details:
The mass of the car is 1200 kg.
The velocity is 25 m/s.
 
Use the equation KE=1/2mv2.
m = mass
v = velocity
 
Put in the mass value and velocity value into the equation.
 
KE=1/2(1200kg)(25m/s)2
KE = 375000 J
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posted by ktqu on 11/7/2007 10:26:07 PM  |  status: Live
Asker's Rating: Helpful   
Response Details:
 
Using the equation h = KE/mg:
 
KE = 375000 (found in part a)
mg = (1200kg)(9.8 m/s2) = 11760  (m is the mass of the car. g is gravity, which is 9.8)
h = ?
 
Put the values into the equation h = KE/mg
h = 37500/11760
h=3.19 m

 
 
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