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posted by  Patso on 11/13/2007 4:19:41 PM  |  status: Closed  

I have the answer, need explanation. Lifesaver points for it.!

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Question Details:

A 2.00-kg mass, attached to a string of length l = 60.0 cm, travels in a

horizontal circle at constant speed. The tension in the string is 23.0 N.

Calculate the angle, θ , between the string and the vertical.
 
 
Answer is 31.6 degrees
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posted by ktqu on 11/13/2007 4:27:33 PM  |  status: Live
Asker's Rating: Lifesaver   
Patso's comment:
"thank you very much"
Response Details:
To answer this question you first need to find the tension in the string when vertical.
T=mg
m=2.00kg
g=9.8m/s2
 
T=19.6 N
 
Now you can use this to make a tension triangle. The vertical side adjacent to θ is 19.6 N, and the hypotenuse is 23 N.
Use cos-1(19.6 / 23) to find the angle θ.
θ = 31.6 degrees
 
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