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posted by  CaLi...:) on 2/15/2008 1:17:24 AM  |  status: Closed  

Physics

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What is the potential energy of a system of two 1.2μC point charges a distance 18cm apart?
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posted by Cdutch88 on 2/15/2008 1:20:42 AM  |  status: Live
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CaLi...:)'s comment:
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Response Details:
PE = kq1q2 / r = 9E9 * 1.2E-6 * 1.2E-6 / 0.18 = 0.072 J
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posted by Gthang on 2/15/2008 1:25:41 AM  |  status: Live
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Response Details:
Hey again
The potential energy can be found using the equation PU=KqQ/r. This is the equation right out of my physics notes, you can try the equation but make sure you double check with some other source.
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