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posted by  Shinbuki on 5/14/2008 5:56:27 PM  |  status: Live  

HELP!Charge of a insultaing sphere

Course Textbook Chapter Problem
General Physics Physics For Scientists And Engineers 7th by Jewett, Serway 24 63
Question Details:
For the configuration shown in the figure below, suppose that a = 5.00 cm, b = 20.0 cm, and c = 25.0 cm. Furthermore, suppose that the electric field at a point 11.5 cm from the center is measured to be 3.10 multiplied by 103 N/C radially inward while the electric field at a point 50.0 cm from the center is 2.50 multiplied by 102 N/C radially outward.
From this information, find the following charges. (Include the sign of the charges.)
(a) the charge on the insulating sphere
C

(b) the net charge on the hollow conducting sphere
C

(c) the total charge on the inner and outer surfaces of the hollow conducting sphere
inner surface
C
outer surface
C
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posted by richmondMike on 5/14/2008 7:20:13 PM  |  status: Live
Asker's Rating: Lifesaver   
Shinbuki's comment:
"ty very much... inputed B wrong.. that was the problem!"
Response Details:
(a) The electric field at r = 0.115m from the center is measured to be E = -3.10 multiplied by 103N/C(E is negative, since it is pointed inward).
, where q is the charge of the insulating sphere.
(b) The electric field at R = 0.500m from the center is measured to be E' = 2.50 multiplied by 102N/C(E' is positive, since it is pointed outward).
, where Q is the net charge of the insulating sphere plus the conductig sphere.
∴The net charge on the hollow conducting sphere is Q - q = 1.15 x 10-8C.
(c) A charge of +q forms on the inner surface to guard the interior of the conductor. So the total charge on the inner surfaces of the hollow conducting sphere is +q = 4.56 x 10-9C. A charge of +Q = 6.95 x 10-9C forms on the outer surface of the conductor.
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