Given the radius of the current loop is r = 0.020m.
Then the area of the current loop is A = π(0.020m)2.
Given the magnetic field is B = 2.00T.
The initial magnetic flux through the loop is
.
In Δt = 0.50s, the final magnetic flux through the loop is
.
Given the wire has a thickness of D = 1.25 x 10-3m and a resistivity of ρ = 1.39 × 10-8 Ωm.
Then the cross-sectional area of the wire is A' = π(D/2)2.
The length of the wire is L = 2πr, where r = 0.020m.
∴The resistance is given by
.
∴The induced current in the loop is
.