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posted by  BrandonECU on 6/18/2008 9:28:42 AM  |  status: Live  

Rotational Motion

Course Textbook Chapter Problem
General Physics College Physics (7th) by Serway, Faughn, Bennett 7 19
Question Details:
A 55.3 kg ice skater is moving at 3.94 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole. She then moves in a circle of radius 0.792 m around the pole.
(a) Determine the force exerted by the horizontal rope on her arms.
(b) What is the ratio of this force to her weight?
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posted by booboo123 on 6/18/2008 1:29:38 PM  |  status: Live
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BrandonECU's comment:
"Thanks a lot"
Response Details:
(a) The force exerted by the rope is the centripetal force:

Fc = mv2/r = (55.3)(3.94)2/(0.792) = 1083.9 N

(b) Ratio:

Fg = mg = (55.3)(9.8) = 541.94 N

Fc/Fg = (1084 N)/(542 N) = 2.00
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