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posted by  VikingMoss on 7/27/2008 4:05:53 AM  |  status: Live  

Electron microscope

Course Textbook Chapter Problem
Algebra Based Physics College Physics (8th) by Young N/A N/A
Question Details:
I have tried .0368, and .038 to no avail.

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Oracle
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posted by Steve (retired) on 7/27/2008 11:22:22 AM  |  status: Live
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"Thanks"
Response Details:
Response:
λ = h/p ....... deBroglie
E = 0.5 mv^2 , p = momentum = mv
E = [m/2][p^2/m^2] = p^2/2m
p = [2mE]^1/2

Part A

λ = h/p = (h )/ (2mE)^1/2

E = (1*10^3) (1.6*10^-19 Joule) = 1.6*10^-16 J

λ = wavelength = (6.6*10^-34) / (2*9.1*10^-31)(1.6*10^-16)^1/2
λ= 3.868*10^-11 m = 0.0368 nm

Part B

Yes
Smaller the wavelength larger is the RP
0.38 *10^-10 < 1*10^-10

Part C

Mass pf proton mp = 1836 me
(0.0368*10^-9) = (h) / (2*1836)(9.1*10^-31)(E1)^1/2
Find E1

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