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posted by  clark005 on 8/3/2008 8:02:17 PM  |  status: Closed  

Stuck, Please help, Will rate!

Course Textbook Chapter Problem
Algebra Based Physics College Physics (7th) by Serway, Faughn, Bennett 26 N/A
Question Details:
What is the speed of a particle whose kinetic energy is equal to twice its own rest energy?
c
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posted by Steve (retired) on 8/3/2008 8:15:26 PM  |  status: Live
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clark005's comment:
"Thanks!"
Response Details:
E = m * c^2 = m0 * c^2 / √(1 - (v/c)^2)
E = m0 * c^2 + KE =  m0 * c^2 +  2 * m0 * c^2 =  3 * m0 * c^2
 
So 1 /  √(1 - (v/c)^2) = 3  
 
So you should get     (v / c)^2 = 8 / 9  and  v / c = 2 * √2 / 3
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