part a)
At a distance of 12.0 cm, both shells are "enclosed" so the total charge is
4.00 + 2.00 = 6.00 x 10-8 coulomb
1/4pe 0 = 8.99 x 109 N-m2/C2
so, E = 8.99 x 109 * 6.0 x 10-8 / 0.122 = 37458 N/C
part b)
At a distance of 20.0 cm, both shells are "enclosed" so the total charge is