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posted by  mari7 on 10/10/2008 9:44:33 AM  |  status: Live  

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General Physics N/A N/A N/A
Question Details:
Suppose that in the same Atwood setup another string is attached to the bottom of m1 and a constant force f is applied, retarding the upward motion of m1. If m1 = 5.60 kg and m2 = 11.20 kg, what value of f will reduce the acceleration of the system by 50%?
f = N
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posted by Justin_08 on 10/12/2008 1:52:18 PM  |  status: Live
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mari7's comment:
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Response Details:
 
 
          Given that the masses are  m1 = 5.60 Kg and  m2 = 11.20 Kg
    ----------------------------------------------------------------------------------------------
 
             
 
       Apply Newtons law for the mass m2 then 
 
                      m2g - T = m2a
  
       for the mass m1
                    T - m1g = m1a
             
      From the above two equations we get
 
                m2g - m2a - m1g = m1a
                                          a = (m2g -  m1g) / (m1+m2)
                                             = ---------- m/s2  
 
     if the acclearation reduced to 50% then the new accelaration is  a1 = a/2
 
   If we exert a force f  on the  mass m1 then the situation is as shown in figure
 
                
  
            Apply Newtons law for the mass m2 then 
 
                      m2g - T = m2*a1
  
       for the mass m1
                    T - m1g - f = m1*a1
             
      From the above two equations we get
 
                m2g - m2*a1 - m1g - f  = m1*a1
                                                  f = m2g - m2*a1 - m1g -  m1*a1
                                                    
                   then we get the applied force  f = ----------- N     
                      
 
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