Given that the mass of the beam is W = 90 N
The length of the beam is L = 10 m
The weight of the printing press is Wp = 360 N
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The situation is as shown in the figure
apply momet of force about point A then we get ( take torque is positive along counter clockwise)
Fa*(0) - W*(AB) - Wp(AC) + Fb*AD = 0
W*(AB) + Wp(AC) = Fb*AD
W*(5.0m) + Wp(8.0m) = Fb*10m
then we get the force Fb = ---------- N
Since the system is in equalibrium then we get
ΣFy = 0
Fa - W - Wp + Fb = 0
Fa = W + Wp - Fb
= ------------- N