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posted by  AKSHAY on 10/12/2008 1:20:21 PM  |  status: Closed  

please help me with this problem

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. A 0.35 kg ball on the end of a string is whirled around in a horizontal circle of radius 0.3-m. The plane of the circle is 1.2 m above the ground. The string breaks and the ball lands 2.0-m away from the point on the ground directly beneath the ball's location when the string breaks. Find the tension in the string at the moment string breaks
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posted by Justin_08 on 10/12/2008 3:33:25 PM  |  status: Live
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AKSHAY's comment:
"thanks alot for your help"
Response Details:
 
 
          Given that the mass of the ball is  m = 0.35 Kg
           The radius of the circle is r = 0.3 m 
 
 
   ------------------------------------------------------------------------------------------
 
               At the time of the string breaks is inward force is equal to outward force . 
                       tention = mU2/r
                              T =  mU2/r
                                 = ----------- N
 
                      
    
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