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posted by  Learning on 6/5/2007 3:41:45 PM  |  status: Live  

Apparant Weight - Physics Cutnell 7th Ch.4 #36

Course Textbook Chapter Problem
N/A cutnell physics 7th ed 4 36
Question Details:
A 95.0 kg person stands on a scale in an elevator.  What is the apparant weight when the elevator is:
a)accelerating upward with an acceleration of 1.8 m/s2
b)moving upward at a constant speed
c)accelerating downward with an acceleration of 1.3 m/s2
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posted by HungryHungryHippo on 6/5/2007 3:57:39 PM  |  status: Live
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Response Details:
The apparent weight is the normal force that acts on the person:

FN + Fg = Felev



(a)
FN = Felev - Fg
FN = (95 kg)(1.8m/s2) - (95 kg)(-9.8m/s2)
FN = 1102 N

(b)
At constant velocity, Felev = 0:
FN = 0 - (95 kg)(-9.8m/s2)
FN = 931 N

(c)
FN = (95 kg)(-1.3m/s2) - (95 kg)(-9.8m/s2)
FN = 807.5 N
Hope I have helped.  Anyone feel free to correct any mistake I may have made.
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