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posted by  Babie Doll on 6/6/2007 5:49:35 PM  |  status: Live  

physics problem

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Classical Physics N/A N/A N/A
Question Details:
Hii, sorry, but I am having trouble with this problem....:( thank you
 
A 54.4 kg ice skater is moving at 4.01 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole. She then moves in a circle of radius 0.794 m around the pole.
(a) Determine the force exerted by the horizontal rope on her arms.
N
(b) What is the ratio of this force to her weight?
(force from part a / her weight)
~ Please rate and I hope it helps! ~ 
 

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posted by HungryHungryHippo on 6/6/2007 5:59:36 PM  |  status: Live
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Babie Doll's comment:
"thanks! :)"
Response Details:
I just posted this answer to a very similar question:

(a) The force exerted by the rope is the centripetal force:

Fc = mv2/r = (54.4)(4.01)2/(0.794) = 1102 N

(b) The ratio is:

Fg = mg = (54.4)(9.8) = 533 N

Fc/Fg = (1102 N)/(533 N) = 2.07
Hope I have helped.  Anyone feel free to correct any mistake I may have made.
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