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posted by  king0468 on 10/6/2008 5:37:43 PM  |  status: Live  

Help Please, I will rate Lifesaver (Probability)

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Suppose each day that you drive to work a traffic light that you encounter is either green with probability 7/16, red with probability 7/16, or yellow with probability 1/8, independent of the status of the light on any other day. If over the course of five days, G, Y, and R denote the number of times the light is found to be green, yellow, or red, respectively,
what is the probability that P[G=2, Y=1, R=2]?
Also, what is the probability P[G=R]?

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posted by Jeffer on 10/13/2008 10:21:22 AM  |  status: Live
Asker's Rating: Lifesaver   
king0468's comment:
"thank you"
Response Details:
So 
P[G] = 7/16
P[R] = 7/16
and P[Y] = 2/16

Five days, each independent...
So you have day 1.. where you have the above probabilities.
Day 2... to day 5.

So you observe the light five times..
5 * P[G] = number of times you would see green (2.3... roughly 2 times)
5 * P[R] = number of times you see red (2.3... roughly 2 times)
and 5 * P[Y] = number of times you see yellow (.625 roughly once)

for 2, 1, 2

You have two days where you see green, and not red or yellow
two days you see red and not the other two
and one day you see yellow.

Will try to get back on this one. :) Hopefully the beginning helps a bit.
:)
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